Câu 16:
Tính limx→(−1)−x2+3x+2∣x+1∣\mathop {\lim }\limits_{x \to {{( - 1)}^ - }} \dfrac{{{x^2} + 3x + 2}}{{\left| {x + 1} \right|}}x→(−1)−lim∣x+1∣x2+3x+2
