Câu 25:
Tính limx→1+x2−x+32∣x∣−1\mathop {\lim }\limits_{x \to {1^ + }} \frac{{\sqrt {{x^2} - x + 3} }}{{2\left| x \right| - 1}}x→1+lim2∣x∣−1x2−x+3 bằng:
