Câu 1:
limx→3(3x2x−3.12x+42x3−6x2+x−3)\mathop {\lim }\limits_{x \to 3} \left( {\dfrac{{3{x^2}}}{{x - 3}}.\dfrac{{12x + 4}}{{2{x^3} - 6{x^2} + x - 3}}} \right)x→3lim(x−33x2.2x3−6x2+x−312x+4) bằng:
