Câu 3:
Cho hàm số$y = {\mkern 1mu} \left\{ {\begin{array}{*{20}{l}}{\frac{2}{{x - 1}},{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} x \in \left( { - \infty ;{\mkern 1mu} {\mkern 1mu} 0} \right)}\\{\sqrt {x + 1} ,{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} x \in \left[ {0;{\mkern 1mu} {\mkern 1mu} 2} \right]}\\{{x^2} - 1,{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} x \in \left( {2;{\mkern 1mu} {\mkern 1mu} 5} \right]}\end{array}} \right..{\mkern 1mu} {\mkern 1mu} $ Tính ta được kết quả:
Câu 3:
Cho hàm sốy = {\mkern 1mu} \left\{ {\begin{array}{*{20}{l}}{\frac{2}{{x - 1}},{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} x \in \left( { - \infty ;{\mkern 1mu} {\mkern 1mu} 0} \right)}\\{\sqrt {x + 1} ,{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} x \in \left[ {0;{\mkern 1mu} {\mkern 1mu} 2} \right]}\\{{x^2} - 1,{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} x \in \left( {2;{\mkern 1mu} {\mkern 1mu} 5} \right]}\end{array}} \right..{\mkern 1mu} {\mkern 1mu} Tính ta được kết quả: