Câu 24. Nếu ∫02f(x)dx=4\smallint _0^2f\left( x \right){\text{d}}x = 4∫02f(x)dx=4 thì ∫02[12f(x)−2]dx\smallint _0^2\left[ {\frac{1}{2}f\left( x \right) - 2} \right]{\text{d}}x∫02[21f(x)−2]dx bằng
