Câu 8. Nếu ∫−14f(x)dx=2\smallint _{ - 1}^4f\left( x \right){\text{d}}x = 2∫−14f(x)dx=2 và ∫−14g(x)dx=3\smallint _{ - 1}^4g\left( x \right){\text{d}}x = 3∫−14g(x)dx=3 thì ∫−14[f(x)+g(x)]dx\smallint _{ - 1}^4\left[ {f\left( x \right) + g\left( x \right)} \right]{\text{d}}x∫−14[f(x)+g(x)]dx bằng
