Câu 33:
Cho ∫12[4f(x)−2x]dx=1.\int\limits_{1}^{2}{\left[ 4f\left( x \right)-2x \right]dx=1.}1∫2[4f(x)−2x]dx=1. Khi đó ∫12f(x)dx\int\limits_{1}^{2}{f\left( x \right)dx}1∫2f(x)dx bằng :
