Câu 40:
Giả sử ∫12(2x−1)lnxdx=aln2+b\int\limits_{1}^{2}{\left( 2x-1 \right)\ln x\text{d}x}=a\ln 2+b1∫2(2x−1)lnxdx=aln2+b, (a;b∈Q)\left( a;b\in \mathbb{Q} \right)(a;b∈Q). Tính a+ba+ba+b.
