Câu 16:
Nếu ∫02f(x)dx=5\int\limits_{0}^{2}{f\left( x \right)\text{d}x}=50∫2f(x)dx=5 và ∫02g(x)dx=−3\int\limits_{0}^{2}{g\left( x \right)\text{d}x}=-30∫2g(x)dx=−3 thì ∫02[f(x)−3g(x)]dx\int\limits_{0}^{2}{\left[ f\left( x \right)-3g\left( x \right) \right]\text{d}x}0∫2[f(x)−3g(x)]dx bằng
