Câu 33:
Cho ∫02f(x)dx=3,∫02g(x)dx=−1\int\limits_{0}^{2}{f\left( x \right)\text{d}x}=3,\int\limits_{0}^{2}{g\left( x \right)\text{d}x}=-10∫2f(x)dx=3,0∫2g(x)dx=−1 thì ∫02[f(x)−5g(x)+x]dx\int\limits_{0}^{2}{\left[ f\left( x \right)-5g\left( x \right)+x \right]\text{d}x}0∫2[f(x)−5g(x)+x]dx bằng:
