Câu 29:
Cho x=2018!.x=2018!.x=2018!. Tính A=1log22018x+1log32018x+ ... +1log20172018x+1log20182018x.A=\frac{1}{{{\log }_{{{2}^{2018}}}}x}+\frac{1}{{{\log }_{{{3}^{2018}}}}x}+\,...\,+\frac{1}{{{\log }_{{{2017}^{2018}}}}x}+\frac{1}{{{\log }_{{{2018}^{2018}}}}x}.A=log22018x1+log32018x1+...+log20172018x1+log20182018x1.