Câu 19:
Tìm I=∫(2x2−1x3−1cos2x) dxI = \int {\left( {2{x^2} - \dfrac{1}{{\sqrt[3]{x}}} - \dfrac{1}{{{{\cos }^2}x}}} \right)\,dx}I=∫(2x2−3x1−cos2x1)dx trên khoảng (0;π2)\left( {0;\dfrac{\pi }{2}} \right)(0;2π).
